HP/Torque questions

Paolo Castellano

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Can anyone here explain what would be the difference between the HP/Torque characteristics of a stock Viper where the torque starts to fall off around the 5,000 RPM range and the HP is still climbing all the way up to 5700 RPM or so and the say, centrifugal blower car applications where the HP and torque are still BOTH increasing from the 5,000 RPM mark. Here is my question in a nutshell: do you have to only have either the HP or the torque to be strong at a given RPM above 5,000 RPM to make power/accelerate/overcome aerodynamic drag/etc... or would the car be more powerful if the HP and Torque were both on the rise as opposed to the torque to be falling off at 5,000 RPM? For example Gary Almond's(I hope I spelled that right) Heffner Supercharged car makes about 565 RWHP and about 635 RWLBS/FT at 4650 RPM(677.4 Peak RWHP and 660 peak RWLBS/FT) . At 4650 RPM, The Sean Roe Supercharger car makes about 515 RWHP and 580 RWLBS/FT(600.6 Peak RWHP and 612.8 peak RWLBS/Ft). I know the Heffner car is running 9 PSi as compared to Roe's 5.5-6. Please note: I am not comparing which car/system is better here, I am only comparing characteristics of different types of systems, to illustrate my point. Also, not to leave out any names and to be politically correct, I know the Doug Levin centrifugal cars have the same general HP/torque characteristics of the Heffner car(Both being Centrifugal Blowers and all, but I happen to have Gary's sheet in front of me as I am doing this post). Heffner Roe and Levin are all great guys and I have spoken to all three and think they all have a lot to offer to the Viper community and we are all lucky to have such great tuners available to suit our particular application. Now, all this political B.S. aside, Here is the thing though, from 4650 RPM to say, 5250 RPM, the centrifugal car's HP and torque are BOTH going up where the Roe supercharger car and the Stock Viper motor have only the HP going up with the torque decreasing. How does this fit into the grand scheme of HP and torque mulitplication at any given speed/RPM where you take HP and/or torque at that RPM X Rear end gear ratio X transmission gear ratio? Paolo Castellano
 

ronviper

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PAOLA torque and horsepower get you out of the hole or bottom end torque is the major factor however after midrange horsepower takes over. Horsepower basically is top end bottom to mid is torque. At a point horsepower and torque will cross and horsepower will continue to climb while torque falls off.
 

joe117

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You probably already know this. Horsepower is equal to torque times rpm divided by 5252. That's why every engine will have the same number of horsepower and foot pounds at the 5252 rpm point. Here's a link to a page that has a very good discussion of torque and horsepower. http://vettenet.org/torquehp.html
 

Mike Brunton

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The article listed is very good, and written by a guy I consider a friend and who has forgotten more about cars than I will ever know, Bruce Augenstein.

Horsepower and torque are really the same thing. People say "at high RPM's HP takes over" - that's not really true it's just that horsepower is a measure of torque in relation to RPM's. If your torque is high, your HP will be high. Since you're multiplying by RPM's, if the torque can stay high as the PRM's rise, youre making alot of power (since a big number by a big number is always going to be larger than a big number multiplied by a small number).

Horsepower is a way to put a guage on how well an engine pulls. You can make alot of HP by revving the crap out of the motor with reasonable power (i.e. Ferrari 360) or by making a ton of torque and not revving it that much (i.e. Viper). A high HP engine has one or the other of these things going on. If you know you have alot of HP, and hence alot of RPM, that means you can take advantage of gearing. Remember that every time you shift you lose torque multiplication. If you can make more horsepower with a longer RPM range, then you can use shorter gears and use the RPM's of the motor to keep you putting that power to the ground.

As for the original question - how does it fit in. Well, since you're torque multiplying by RPM's to get HP, the torque can be falling but as long as it's not falling quicker than the RPM's are rising, then the HP curve is still going up. At the point where RPMs are rising as fast as torque is falling the HP graph would be flat, and if torque is falling faster than RPM's are rising then the HP graph is dropping. SO, comparing the Roe to the Heffner car... if the Roe car has torque falling and the Heffner car has torque rising, then the HP of the Heffner car is going to be rising alot quicker than that of the Roe car. If the ultimate HP at the wheels is the same (which it isn't), then you could presume that the Roe kit had "more area under the curve" which is a good thing. The Heffner kit makes more RWHP though - and this is why... because it's still making torque from 4600-5200RPM whereas the Roe kit is fallign off in torque, so this contributes to the Heffner's higher end RWHP number.

Which is better? No idea. But, if you have a couple of overlayed dyno charts, you can get an idea of the net effect. Torque is what moves the car - period. Horsepower does NOT pull the car - the ONLY thing you feel is TORQUE. The only thing that moves the car is TORQUE, whether it's at 500RPM or 5,000RPM. The idea that "horsepower takes over at high RPM" isn't accurate... I know what it means but it's not correct. You will feel the MOST acceleration with the most torque. If you make more HP, that means you make good torque higher in the RPM range meaning you can stay in that gear longer giving you better *OVERALL* acceleration, but torque is what you feel and what gives you the power.

The net effect will be... the Roe kit will feel like power is "dropping off" from 4600 to 5200RPM compared to a Heffner car, which will feel like it's "still pulling". In reality, they will BOTH still be pulling, but the Heffner car will feel like it's pulling harder, and harder, and harder as the RPMs rise whereas the Roe car will feel like the acceleration is "leveling off" from 4600 to 5200RPM's. Of course I'm just going by what you posted - I havent seen the graphs myself together.

The best way to figure out the most usable power would be to go out and run your car through the gears. You will notice that you shift, say around 5000RPM. When you shift, you fall back down to some RPM level - maybe 4000RPM (I don't know what the RPM drop is per gear in a Viper, just guessing), but let's say it's 1,000RPM. Now, 4,000-5,000RPM would be your "power range" that you drive in for max acceleration. blank off every other area of those dyno sheets and just look at 4,000-5,000. The one that looks more impressive IN THIS RANGE will be the one that is going to feel more impressive to the driver. The 1,000-4,000 range is only going to be used in low-accleration or in 1st gear (which is pretty useless anyways in a modified Viper). The sub-4,000RPM graph will give you an idea of the around-town driveability of the car and how it's going to feel on the street, but that 4,000-5,000 range is ALL THAT MATTERS in terms of pure acceleration. Remember, it's the area UNDER the curve - the average power within your acceleration range that counts. I'm just guessing it's 4,000-5,000 - might be a few hundred RPM higher or lower each way.

Can you post the graphs?
 

Tom and Vipers

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HP is THE parameter of interest.

For any form of racing, the area under the HP curve for the application is what is to be maximized.

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Regarding top end.

Consider the point where your car "runs out of breath."

If you could simply maintain that torque for an additional 1000 rpm, that would correspond to a substantial increase in HP!

If you've raced people on the street and you have a high reving engine, it is so cool when you are dead even with the other guy and it becomes clear that the first guy that has to shift loses - and it is the other guy!

========================================

Regarding centrifugal superchargers, pressure is proportional to the square of the engine rpm.

So if a centrifugal makes 8 psi at 6000 rpm, you will have 2 psi at 3000. Correspondingly, the torque improvement at 3000 rpm is not very dramatic, but at 6000 it is - and so is HP!

The "danger" with a centrifugal is that if you are racing a guy, and you are even, you will beat him if you can turn just a little more rpm and get that bigger corresponding boost.

(Remember it is area under the curve so the ultimate operation range will have the max HP peak more or less in the CENTER of the operating range. Of course, with a centrifugal, the HP peak basically keeps increasing with rpm so the more you rev the engine the more HP you make until something happens. Float the valves, slip the supercharger belt, run out of fuel, etc. Some of these failure can be disasterous such as running out of fuel. Then we get "Burn Baby Burn" as far as the pistons are concerned.)

You can sort of pace yourself with centrifugals if you want to marginally beat a slower car. A fast opponent will force you to redline or perhaps beyond if you try to win.
=========================================

Obviously a positive displacement supercharger blows a centrifugal away at 3000 rpm.

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For daily driving it is a lot of fun to grunt around ripping the tires at low rpm.

==========================================

For the mad scientists out there, running both a positive displacement and a centrifugal is possible. The PDSC essentially makes the engine "bigger" while the CSC solves the running out of breath on top end problem.

...and they even wouldn't even get in each others physical way!
 

Tomcat

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And there you have it. The one who shifts first looses. The one big reason I will not do 355's on my next Viper. Thanks for taking the time to educate me on this subject. It never clicked before now!

tw
 
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Paolo Castellano

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<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Mike Brunton:
Since you're multiplying by RPM's, if the torque can stay high as the RPM's rise, youre making alot of power (since a big number by a big number is always going to be larger than a big number multiplied by a small number).

If you can make more horsepower with a longer RPM range, then you can use shorter gears and use the RPM's of the motor to keep you putting that power to the ground.

SO, comparing the Roe to the Heffner car... if the Roe car has torque falling and the Heffner car has torque rising, then the HP of the Heffner car is going to be rising alot quicker than that of the Roe car.
If the ultimate HP at the wheels is the same (which it isn't), then you could presume that the Roe kit had "more area under the curve" which is a good thing. The Heffner kit makes more RWHP though - and this is why... because it's still making torque from 4600-5200RPM whereas the Roe kit is fallign off in torque, so this contributes to the Heffner's higher end RWHP number.

Which is better? No idea. But, if you have a couple of overlayed dyno charts, you can get an idea of the net effect. Torque is what moves the car - period. Horsepower does NOT pull the car - the ONLY thing you feel is TORQUE. The only thing that moves the car is TORQUE.
You will feel the MOST acceleration with the most torque. If you make more HP, that means you make good torque higher in the RPM range meaning you can stay in that gear longer giving you better *OVERALL* acceleration, but torque is what you feel and what gives you the power.

The net effect will be... the Roe kit will feel like power is "dropping off" from 4600 to 5200RPM compared to a Heffner car, which will feel like it's "still pulling". In reality, they will BOTH still be pulling, but the Heffner car will feel like it's pulling harder, and harder, and harder as the RPMs rise whereas the Roe car will feel like the acceleration is "leveling off" from 4600 to 5200RPM's. Of course I'm just going by what you posted - I havent seen the graphs myself together.

The best way to figure out the most usable power would be to go out and run your car through the gears. You will notice that you shift, say around 5000RPM. When you shift, you fall back down to some RPM level - maybe 4000RPM (I don't know what the RPM drop is per gear in a Viper, just guessing), but let's say it's 1,000RPM. Now, 4,000-5,000RPM would be your "power range" that you drive in for max acceleration. blank off every other area of those dyno sheets and just look at 4,000-5,000. The one that looks more impressive IN THIS RANGE will be the one that is going to feel more impressive to the driver. The 1,000-4,000 range is only going to be used in low-accleration or in 1st gear (which is pretty useless anyways in a modified Viper). The sub-4,000RPM graph will give you an idea of the around-town driveability of the car and how it's going to feel on the street, but that 4,000-5,000 range is ALL THAT MATTERS in terms of pure acceleration. Remember, it's the area UNDER the curve - the average power within your acceleration range that counts. I'm just guessing it's 4,000-5,000 - might be a few hundred RPM higher or lower each way.

Can you post the graphs?

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Mike, I wish I could post the graphs, but I do not know how to . I kind of overlayed the Roe #'s onto the Heffner graph on paper and it seems that the Roe Hp is higher until about 3650 RPM and the torque is higher until about 4,000 RPM. I have the Orbital Gears chart of MPH/RPM in each gear with the stock 3.07. Shifting at 5500 RPM 1-2 will yield 3750 RPM in 2nd, 5500 RPM 2-3 will yield 4,000 RPM in 3rd, 5500 RPM 3-4 will yield 4250 RPM in 4th, 5500 RPM 4-5 will yield 4050 RPM in 5th. Now the Roe package Hp is still on the rise from 4,000 all the way to 5800 RPM but the torque is falling 4,000-5800 RPM. The Heffner car's HP and torque are both rising 4,000-5250 RPM, albeit the slope of the Heffner HP curve is steeper, it is also running higher boost so it is unfair to compare apples to apples for the absolute slope of the HP curve. Mike, you said the Twin-Screw car will feel as it is dropping off compared to the Centrifugal one. Is this because total acceleration is a function of both the HP and Torque through that range? I still do not exactly understand. Sorry, Paolo
 

Mike Brunton

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<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Paolo Castellano:
I kind of overlayed the Roe #'s onto the Heffner graph on paper and it seems that the Roe Hp is higher until about 3650 RPM and the torque is higher until about 4,000 RPM. [/b]<HR></BLOCKQUOTE>

This sounds right. Sean's kit with the autorotor SC will provide a lot of boost right off the line whereas the centrifugal unit will need to spool up - hence Roe's SC is more of a "flatter line" whereas the Heffner kit will have a higher peak but take some more RPM's to get there.

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>
I have the Orbital Gears chart of MPH/RPM in each gear with the stock 3.07. Shifting at 5500 RPM 1-2 will yield 3750 RPM in 2nd, 5500 RPM 2-3 will yield 4,000 RPM in 3rd, 5500 RPM 3-4 will yield 4250 RPM in 4th, 5500 RPM 4-5 will yield 4050 RPM in 5th.
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Ok, so your power range when you're racing is going to be 3,750 to 5,500RPM's. Concentrate on this area of the graph - this is where you want to look if you're looking for the absolute best acceleration.

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>
Now the Roe package Hp is still on the rise from 4,000 all the way to 5800 RPM but the torque is falling 4,000-5800 RPM. The Heffner car's HP and torque are both rising 4,000-5250 RPM, albeit the slope of the Heffner HP curve is steeper, it is also running higher boost so it is unfair to compare apples to apples for the absolute slope of the HP curve.
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This makes sense. To get horsepower you multiply torque by RPM (and divide by a correction factor), so every 100RPM more on the graph, the HP is going up by 100 times whatever the torque went up. If the torque went down, as long as it didn't fall 100lb-ft in that 100RPM range, the HP will still be climbing. It's like if you were in your car going 70mph then you go in neutral... then you go up a gradual slope. You're still moving forward and going up the hill but more and more slowly, until you eventually come to a stop and start rolling back. If you were in 3rd rather than neutral, you could keep accelerating up the hill and you would get up there faster. Sort of like the graphs... the Heffner kit is still rising in torque at that RPM so the HP is going to be going up quicker. The Roe kit will still make HP so long as the RPM's rise quicker than the torque falls, so as long as the torque isn't going down by more than 100lb-ft for each 100RPM, the HP is still going up.

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>
Mike, you said the Twin-Screw car will feel as it is dropping off compared to the Centrifugal one. Is this because total acceleration is a function of both the HP and Torque through that range? I still do not exactly understand. Sorry, Paolo
<HR></BLOCKQUOTE>

Not so much a function of both HP and torque... you can't feel horsepower. Nobody ever felt an ounce of horsepower, they only feel torque.

Torque is a force applied times the distance on a lever.

Power is defined as the amount of work done over a period of time.

Work is the force applied in relation to the distance.

If you're taking off your lug nuts, you want to use a long bar to get more leverage (torque). If I gave you a 3" long ratchet to take off your lug nuts, you would have to push REALLY hard (remember torque is force times distance, so if the distance goes down, the force must go up to produce the same amount of torque). If I said you had to take your lug nuts off and you had an hour to do it, you could turn them really slow. If I said you had 1 minut to do it, you would have to work very quickly and turn them very quick to make it in time. Even though the amount of energy you output might be the same, you would have to use more "power" to take them off quicker. Like running a 100 yards.. if you take 10 minutes to do it, no problem. If you do it in 30 seconds, you gotta be moving fast and you are using more power to do it more quickly.

So, you can't really measure "power" because it's force and time. It's sort of like "intensity" if you will... I mean, if I have to travel a mile, it's more "intense" if I do it in 5 minutes than if I do it in 5 hours. So in your car, if the crank is turning with a force of 500lb-ft but it's going at 5,000RPM, it's making a lot more power than if it was making 500lb-ft at 1,000RPM. Does that help?

So if your car can make 500lb-ft of torque at a faster rate (higher RPM) then it's more "intense" and it's making more power than if it did it at a slower rate. Horsepower is "how much turning force can the engine output and how quickly can it do it". If it can only produce 300lb-ft, but if it can do that at 20,000RPM then that's very "intense" and hence makes a lot of horsepower (this engine would be making 1,100hp from it's 300lb-ft of torque because it can produce that 300lb-ft at such a high RPM).

Every engine has a usable RPM ranges. The only way to make more horsepower is to make more torque or make the same torque but at a higher RPM. All the things we do to "open up" our engine for air flow helps stuff air in and allows the engine to make a little more torque in the RPM range which means more horsepower. Once you consider gears, horsepower gets important. In the example of the 20,000RPM engine.. well, it's "only" making 300lb-ft of torque right? Well let's say I want to turn a wheel on a car with that engine... I would need to gear it down. Let's say I want to turn the wheel 1000 times a minute and I want to do that at it's maximum power level. Well, on a car that makes max torque at 5,000RPM, I need to reduce the speed by 5 times. I could do that with a 5:1 transmission gear and a 1:1 rear end, or I would use maybe a 3:1 rear end and a 1.5:1 transmission gear. So, we know gears multiply the torque right? So I am reducing the RPM's by 5 which means I am multiplying the torque by 5. So my 5,000RPM engine that makes 500lb-ft of torque is putting 2,500lb-ft of torque to the wheels.

Now, our 20,000RPM engine is sweeter! It makes a maximum of 300lb-ft but at 20,000RPM. To get our wheels moving at 1000 times a minute, we need to reduce the power by 20 times. We might use a 5:1 transmission gear and a 4:1 rear gear. Now, we reduced it 20 times but we multiplied our torque 20 times as well. So our whimpy 300lb-ft of torque engine is putting 6,000lb-ft of torque to the rear wheels.

So we have car A that makes 500lb-ft at 5,000RPM. It has more torque than car B. But car B makes 300lb-ft at a HUGE RPM level (meaning BIG horsepower) which means we can gear it and get a TON of power to the wheels!

This is getting long
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The only thing you ever feel is torque. If two identical cars have the same setup (gears, wheels, weight) but different torque at a given RPM, the car with the higher torque WILL be accelerating quicker. The RPM ranges on both superchargers are the same, so forget about gearing and horsepower, and just concentrate on torque in the RPM range you will be using the car. For maximum acceleration, you will be going from 3,750 to 5,500RPM. Whichever supercharger has the higher torque numbers between those two RPM's WILL be the quicker accelerating car - no if's and or but's. Getting it to the ground is another matter.

On the street, you spend most of your time between 1,500 and 4,000RPM... so a twin screw with it's instant torque will feel real nice on the street. On the track, the one with the most average torque (area under the curve) will be the quicker one.

That's why I would never want a Supra with 900HP. It has a huge turbo that takes forever to spool up. The torque curve is so peaky... it might make 700RWTQ at 6000RPM, but it might also make 200RWTQ at 2,000RPM. It's a weak car until it 'spools up'. For street driving, lots of torque low in the RPM range feels nice - thats why a Viper "feels" faster than a Ferrari 360. When you get on it, all that counts is the average torque in your acceleration RPM range.


If anyone is still reading at this point, I hope it helped
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Paolo Castellano

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<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by joe117:
You probably already know this. Horsepower is equal to torque times rpm divided by 5252. That's why every engine will have the same number of horsepower and foot pounds at the 5252 rpm point. Here's a link to a page that has a very good discussion of torque and horsepower. http://vettenet.org/torquehp.html


<HR></BLOCKQUOTE>

Joe, I read the article, very informative! Now I know why the HP and torque always seem to cross @ 5250! I get it! Now I know what Mike was saying. Paolo
 
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