SRT10 vs ZO6......3.5 car lengths

[M. ROD]

Fooling arround with a pen and a piece of paper resulted into this;

Its like a "method" to measure the distance between cars. It can be apply to 0-60, 0-100, 1/4 mile, one mile, etc,etc... Probably some of you already know this so please correct me if I'm wrong.

Based on Motor Trend's last issue of Viper vs Vette:

The 1/4 mile:

Viper: 12.3 sec.
Vette: 12.8 sec.

1/4 mile = 1320ft

Viper's rate : 1320ft/12.3 sec. = 107.317ft/s
Vette's rate : 1320ft/12.8 sec. = 103.125ft/s

Now multiply the Vette's rate with the Viper's ET to know the position of the Vette when the Viper stoped the timers.

(103.125ft/s)(12.3s)= 1268.44ft

So when the Viper stoped the timers the Vette had covered 1268.44ft of 1320ft.

(1320ft)-(1268.44ft)= 51.56ft

The Vette was 51.56ft behind the Viper.
Vette's length= 179.7in = 14.975ft

So (51.56ft)/(14.975ft)= 3.44

Lets round that up to 3.5

If this "method" is correct then the Viper won by 3.5 car lengths

Now is this correct? Can some of you math experts check this out? Thanks for your time, Mike.

 

[MES]

It's not a straight math equation as both cars accelerate slower at higher speeds. Your calculations are based on constant acceleration from start to finish.

When the Viper hit the end we'll say the Z06 was traveling at 110 MPH then it finished at 114 for an average speed of say 112 MPH (the average speed during the last 1/2 sec) It took the Z06 .5 sec to hit the finish after the Viper so at 112MPH it would have covered 82 feet, or have been 5 1/2 car lengths behind the Viper. That is about what I would expect as a rule of thumb .1 sec = 1 car length when your talking about 12 sec cars.

I'm having flash backs of my 8th grade Math class

 

[M. ROD]

Thank You!!!

 

[M. ROD]

Thank You!!!