HELLO...HELLO...HELLO...anybody out there listening? The VIPAIR replaces UNDERHOOD HEATED AIR with OUTSIDE AMBIENT AIR FROM THE FRONT FASCIA!!!! What do you think the temperature difference is between these two sources...maybe 400+ degrees cooler ambient than underhood? Now do your calculations to see if the VIPAIR adds much cooler air to your airbox intake, and therefor, additional HP & TQ! I think we are dealing with a lot of 10 IQs not 10 HP!
Wow! 400 degrees more underhood. Lets see on a 100 degree day that would be 500 degrees underhood. Wow!
Now how did the air passing through the radiator get hotter than the coolant it is cooling? I can't. Therefore the air immediately behind the radiator must be less than coolant temperature. I would guess the temperature in that region would max out somewhere near 150-200F when the car is moving (stationary temps would rise, but fall rapidly under motion). That would leave a delta temp of about 100F if all of the incoming air was from underhood. I would think the amount of underhood air versus outside air would be less than 50%. That leaves more like a 50F difference max.
Now chemistry experts, what is the difference in density of air at 80F versus 130? The ideal gas law is pV/T=constant (pV=nRT for you chemists). The pressure is a constant. Therefore the volume occupied is proportional to the temperature. Note the temp I will use are 300K (about 27C) and 325K. That results in about an 8% decrease in "air volume" at the higher temp. 8% for a Viper producing 410 RWHP is about 30 RWHP. Pretty measureable decrease. Now that is kind of a maximum scenario. But it does tell you that temperature has a real impact.
Now I severely doubt that you will find a temperature decrease as large as mentioned above.
Now since the Viper has a sensor measuring the inlet charge temperature, why doesn't someone with the cold air system just drive with the original and the new system and measure the real charge temp under normal driving conditions. I would hope any tuner worth his/her salt would be able to decipher the sensor voltage into a temperature. Then a very quick calculation can indicate the potential power increase due to the reduced charge temp.